Check if Range element exists in Set using Python

Given a set, test if any element from range exists in set.

Input : test_set = {1, 5, 2, 7, 3, 4, 10, 14}, strt, end = 8, 12
Output : True 
Explanation : 10 is in range and present in set, hence True.

Input : test_set = {1, 5, 2, 7, 3, 4, 15, 14}, strt, end = 8, 12
Output : False
Explanation : No element in range is present.

Method #1 : Using any()
In this, each element is iterated from range to check for existence in set. The any() is used to check if any of range element is found.

# Python3 code to demonstrate working of
# Test if any range element exists in set
# Using any()

# initializing strings set
test_set = {1, 5, 2, 7, 3, 4, 10, 14}

# printing original string
print("The original set is : " + str(test_set))

# initializing range 
strt, end = 8, 12 

# any() tests for all the elements in range
# range() creates range
res = any(ele in test_set for ele in range(strt, end))

# printing result
print("Does range element exists ? : " + str(res))

Output

The original set is : {1, 2, 3, 4, 5, 7, 10, 14}
Does range element exists ? : True

Method #2 : Using set.intersection() + bool()
In this, intersection of elements from range is tested using intersection(), and bool() is used get the presence of any element, to know set is not empty.

# Python3 code to demonstrate working of
# Test if any range element exists in set
# Using set.intersection() + bool()

# initializing strings set
test_set = {1, 5, 2, 7, 3, 4, 10, 14}

# printing original string
print("The original set is : " + str(test_set))

# initializing range 
strt, end = 8, 12 

# intersection() gets the set intersection with range
# range() creates range
res = bool(test_set.intersection(range(strt, end)))

# printing result
print("Does range element exists ? : " + str(res))

Output

The original set is : {1, 2, 3, 4, 5, 7, 10, 14}
Does range element exists ? : True