GATE CS 2025 Set 2 | Question 14

MCQ · 1 mark · −0.33

Let \(L, M\), and \(N\) be non-singular matrices of order 3 satisfying the equations

\(L^{2} = L^{-1}\) , \(M = L^{8}\) and \(N = L^{2}\).

Which ONE of the following is the value of the determinant of \((M - N)\)?

  1. Option A: 0 (correct)
  2. Option B: 1
  3. Option C: 2
  4. Option D: 3

Answer

(A)

Explanation

Multiply \(L^{2} = L^{-1}\) on the right by \(L\) to get \(L^{3} = I\). Powers of \(L\) therefore repeat every three steps:

\[M = L^{8} = (L^{3})^{2}L^{2} = L^{2} = N.\]

So \(M - N\) is the zero matrix, and its determinant is 0. Non-singularity only guarantees that \(L^{-1}\) exists; it says nothing about the difference \(M - N\), so the non-zero options cannot occur.

Answer: A